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  • Question 1 - Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart...

    Correct

    • Transthoracic echocardiogram (TTE) can be used to investigate the function of the heart in patients with suspected heart failure. The aim is to measure the ejection fraction, but to do that, the stroke volume must first be measured. How is stroke volume calculated?

      Your Answer: End diastolic volume - end systolic volume

      Explanation:

      Cardiac output = stroke volume x heart rate

      Left ventricular ejection fraction = (stroke volume / end diastolic LV volume ) x 100%

      Stroke volume = end diastolic LV volume – end systolic LV volume

      Pulse pressure = Systolic Pressure – Diastolic Pressure

      Systemic vascular resistance = mean arterial pressure / cardiac output
      Factors that increase pulse pressure include:
      -a less compliant aorta (this tends to occur with advancing age)
      -increased stroke volume

    • This question is part of the following fields:

      • Physiology And Biochemistry
      29.1
      Seconds
  • Question 2 - Which of the following best explains the statement Epinephrine is formulated as 1...

    Incorrect

    • Which of the following best explains the statement Epinephrine is formulated as 1 in 1000 solution

      Your Answer: 1 mg per 1000 ml solution

      Correct Answer: 1000 mg per 1000 ml solution

      Explanation:

      The statement Epinephrine is formulated as 1 in 1000 solution means 1 gm epinephrine is present in 1000 ml of solution.

    • This question is part of the following fields:

      • Pharmacology
      34.6
      Seconds
  • Question 3 - A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He...

    Incorrect

    • A 41-year-old man, with symptomatic tracheal compression is scheduled for a thyroidectomy. He has previous personal history of hyperthyroidism, controlled by a carbimazole prescription.
      He has previously presented to the emergency department with dyspnoea and stridor, for which the surgery is indicated. Prior to his thyroidectomy, excessive bleeding is controlled for by ligation of the superior thyroid artery.
      The superior thyroid artery branches into the superior laryngeal artery which is closely related to a structure which upon injury will cause loss of sensation in the laryngeal mucosa.

      What is the name of this structure?

      Your Answer: Left recurrent laryngeal

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The internal laryngeal nerve provides sensory innervation to the laryngeal mucosa, and injury to it will cause loss of sensation.

      The internal laryngeal nerve lies inferior to the piriform recess mucous membrane, placing it at high risk of irritation or damage by objects which become lodged in the recess.

      The internal laryngeal artery branches off the superior laryngeal artery accompanied by the superior laryngeal nerve, inferior to the thyroid artery which branches off the superior thyroid artery close to its bifurcation from the external carotid artery.

    • This question is part of the following fields:

      • Anatomy
      199
      Seconds
  • Question 4 - A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse...

    Incorrect

    • A 40-year-old obese woman has complaints of heartburn and regurgitation that is worse on lying flat. The doctor suspects gastroesophageal reflux due to a hiatus hernia. Lifestyle modifications to lose weight and antacids are prescribed to her.

      At which level of the diaphragm will you find an opening for this problem?

      Your Answer: T6

      Correct Answer: T10

      Explanation:

      Hiatus is an opening in the diaphragm. A hiatal hernia is a protrusion of the upper part of the stomach through an opening in the diaphragm, the oesophageal hiatus, into the thorax. The oesophageal hiatus occurs at the level of T10 in the right crus of the diaphragm.

      Other important openings in the diaphragm:
      T8: vena cava, terminal branches of the right phrenic nerve
      T10: oesophagus, vagal trunks, left anterior phrenic vessels, oesophageal branches of the left gastric vessels
      T12: descending aorta, thoracic duct, azygous and hemi-azygous vein

      An opening in the diaphragm is called a hiatus. The oesophageal hiatus is at vertebral level T10. A hiatus hernia is where the stomach bulges through the oesophageal hiatus hence the name – hiatus hernia.

    • This question is part of the following fields:

      • Anatomy
      21.7
      Seconds
  • Question 5 - The following haemodynamic data is available from a patient with pulmonary artery catheter...

    Incorrect

    • The following haemodynamic data is available from a patient with pulmonary artery catheter inserted:

      Pulse rate - 100 beats per minute
      Blood pressure - 120/70mmHg
      Mean central venous pressure (MCVP) - 10mmHg
      Right ventricular pressure (RVP) - 30/4 mmHg
      Mean pulmonary artery wedge pressure (MPAWP) - 12mmHg

      Which value best approximates the patient's coronary perfusion pressure?

      Your Answer: 56mmHG

      Correct Answer: 58mmHg

      Explanation:

      Coronary perfusion pressure(CPP), the difference between aortic diastolic pressure (Pdiastolic) and the left ventricular end-diastolic pressure (LVEDP), is mainly determined by the formula:

      CPP = Pdiastolic -LVEDP
      where
      Pdiastolic is the lowest pressure in the aorta before left ventricular ejection and
      LVEDP is measured directly during a cardiac catheterisation or indirectly using a pulmonary artery catheter. The pulmonary artery occlusion or wedge pressure approximates best with LVEDP.

      Using this patient’s haemodynamic data:

      CPP = Pdiastolic – MPAWP
      COO = 70 – 12 = 58mmHg

    • This question is part of the following fields:

      • Clinical Measurement
      29.4
      Seconds
  • Question 6 - A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia....

    Incorrect

    • A 77-year-old woman is scheduled for day case cataract surgery under local anaesthesia. She has no cardiac or respiratory problems. Lisinopril is being used to treat her hypertension, which is under control.

      Which of the following preoperative investigations are the most appropriate for this patient?

      Your Answer: ECG only

      Correct Answer: No investigations

      Explanation:

      Because the patient has mild systemic disease, he is ASA 2 and the procedure will be performed under local anaesthesia.

      The following factors should be considered when requesting preoperative investigations:

      Indications derived from a preliminary clinical examination
      Whether or not a general anaesthetic will be used, the possibility of asymptomatic abnormalities, and the scope of the surgery.

      No special investigations are needed if the patient has no history of significant systemic disease and no abnormal findings on examination during the nurse-led assessment.

    • This question is part of the following fields:

      • Clinical Measurement
      30.7
      Seconds
  • Question 7 - A 24-year old female is brought to the emergency room due to urticarial...

    Incorrect

    • A 24-year old female is brought to the emergency room due to urticarial rash and shortness of breath. Her mother reported that, prior to the symptoms, she took Co-amoxiclav (Augmentin) for her present ear infection. She also reported that she had no previous exposure to penicillin or any other related antibiotics.

      Which of the following can help to differentiate between type 1 and type II hypersensitivity reaction in this case?

      Your Answer: Intradermal skin testing

      Correct Answer: IgE assay specific for amoxycilloyl

      Explanation:

      Serum specific IgE assays against allergen sources/molecules are the most commonly used in vitro diagnostic approach. The measurement of specific IgE recognizing allergenic epitopes can be achieved both through the usage of single reagents (singleplex) or with a pre-defined panel of a number of molecules to be tested simultaneously (multiplex).

      Several clinical entities have been described and those occurring immediately after drug exposure are immunoglobulin E (IgE)-mediated and explored by skin testing and by the in vitro measurement of serum-specific IgE. The sensitivity of these tests is not 100% and even for patients with a clear positive history, a drug provocation test may be required in order to confirm the diagnosis. The advantages of the in vitro determination of specific IgE antibodies when compared with in vivo testing are that the former poses no direct risk to the patient and does not require personnel with expertise. Even though in vitro tests are recommended in immediate hypersensitivity reactions, their exact place in the diagnostic procedure is not clear and certain authors do not use this method in daily practice. In one study, in terms of sensitivity, 11 of 26 patients (42%) with negative skin tests and a positive drug provocation challenge (or repeated clinical history) had specific IgE to benzylpenicilloyl or amoxicilloyl (4). The specificity of the test was 95–100%. Therefore, IgE measurements can avoid a potentially harmful drug provocation test.

      An elevated serum tryptase does not differentiate between type 1 and type 2 hypersensitivity reaction. It indicates mast cell degranulation.

      RAST is a useful aid to improve the overall diagnosis of drug allergies by using radioactive detection. This, however, is now rarely used.

      Quantification of basophil activation by CD63 expression can be done by flow cytometry, which forms the basis of experimental drug-induced basophil stimulation tests.

    • This question is part of the following fields:

      • Pathophysiology
      151.6
      Seconds
  • Question 8 - The following are results of some pulmonary function tests:

    Measurement - Predicted result -...

    Incorrect

    • The following are results of some pulmonary function tests:

      Measurement - Predicted result - Test result
      Forced vital capacity (FVC) (btps) - 3.21 - 1.94
      Forced expiratory volume in 1 second (FEV1) (btps) - 2.77 - 1.82
      FEV1/FVC ratio % (btps) - 81.9 - 93.5
      Peak expiratory flow (PEF) (L/second) - 6.55 - 3.62
      Maximum voluntary ventilation (MVV) (L/minute) - 103 - 87.1

      Which statement applies to the results?

      Your Answer: These pulmonary function tests are normal

      Correct Answer: The patient has a moderate restrictive pulmonary defect

      Explanation:

      Severity of a reduction in restrictive defect (%FVC) or obstructive defect (%FEV1/FVC) predicted are classified as follows:

      Mild 70-80%
      Moderate 60-69%
      Moderately severe 50-59%
      Severe 35-49%
      Very severe <35% This patient has a %FVC predicted of 60.4% and this corresponds to a moderate restrictive deficit. %FEV1/FVC ratio is 93.5%. FEV1/FVC ratio 80% < predicted and VC < 80% = mixed picture. FEV1/FVC ratio 80% < predicted and VC > 80% = obstructive picture.

      FEV1/FVC ratio 80% > predicted and VC > 80% = normal picture.

      FEV1/FVC ratio 80% > predicted and VC < 80% predicted= restrictive picture. The integrity of the alveolar-capillary barrier is measured by carbon monoxide transfer factor (TLCO) and carbon monoxide transfer coefficient (KCO). These values are seen to be reduced in emphysema, interstitial lung diseases and in pulmonary vascular pathology. However, the KCO (as % predicted) is high in extrapulmonary restriction (pleural, chest wall and respiratory neuromuscular disease), and in loss of lung units provided the structure of the lung remaining is normal. The KCO distinguishes extrapulmonary (high KCO) causes of ‘restriction’ from intrapulmonary causes (low KCO).

    • This question is part of the following fields:

      • Clinical Measurement
      86.5
      Seconds
  • Question 9 - The production of carbon dioxide and water occurs during cellular respiration, which involves...

    Incorrect

    • The production of carbon dioxide and water occurs during cellular respiration, which involves an energy substrate and oxygen. For a patient, the respiratory quotient is calculated as 0.7.

      Which of the following energy substrate combinations is the most likely in this patient's diet?

      Your Answer: High carbohydrate, high fat and low protein

      Correct Answer: Low carbohydrate, high fat and low protein

      Explanation:

      The respiratory quotient (RQ) is the proportion of CO2 produced by the body to O2 consumed per unit of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet.

      Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars – RQ = 1
      Fats – RQ = 0.7
      Proteins – RQ is 0.9
      Ethyl alcohol – RQ = 0.67

    • This question is part of the following fields:

      • Pathophysiology
      0.9
      Seconds
  • Question 10 - Which of the following statements about the cricoid cartilage is true? ...

    Incorrect

    • Which of the following statements about the cricoid cartilage is true?

      Your Answer:

      Correct Answer: The lower border is attached to the first tracheal ring

      Explanation:

      The cricoid cartilage is a hyaline cartilage ring surrounding the trachea. It provides support for key phonation muscles.

      The inferior border of the cricoid cartilage is attached to the thyroid cartilage and the inferior border is attached to the first tracheal ring through the cricotracheal ligament.

      Application of pressure to the cricoid cartilage to reduce risk of aspiration of gastric contents (Sellick manoeuvre) does not stop tracheal aspiration and cannot stop regurgitation into the oesophagus.

      A force of 44 newtons to the cricoid cartilage is needed to control regurgitation.

    • This question is part of the following fields:

      • Antomy
      0
      Seconds
  • Question 11 - An elderly man complains of a vague lump near his stomach to his...

    Incorrect

    • An elderly man complains of a vague lump near his stomach to his physician. On examination, the lump is visible on coughing and is found within Hesselbach's triangle.

      Which of the following is true regarding the borders for this triangle?

      Your Answer:

      Correct Answer: Inguinal ligament inferiorly, inferior epigastric vessels laterally, lateral border of rectus sheath medially

      Explanation:

      The inguinal triangle of Hesselbach is an important clinical landmark on the posterior wall of the inguinal canal. It has the following relations:
      Inferiorly – medial third of the inguinal ligament
      Medially – lower lateral border of the rectus abdominis
      Laterally – inferior epigastric vessels

      Direct inguinal hernia is when the bowel bulges directly through the abdominal wall. These hernias usually protrude through Hesselbach’s triangle

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 12 - Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom...

    Incorrect

    • Conclusive evidence suggests that rate for the prevalence of schizophrenia in United Kingdom is around 1%.

      Which term can be used to describe that?

      Your Answer:

      Correct Answer: Endemic

      Explanation:

      An epidemic is declared when the increase in a give disease is above a certain level in a specific interval of time.

      An endemic is the general, usual level of a disease in a population at a particular time.

      A pandemic is an epidemic that is spread across many countries and continents.

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 13 - Which of the following statement is true regarding the paediatric airway? ...

    Incorrect

    • Which of the following statement is true regarding the paediatric airway?

      Your Answer:

      Correct Answer: The larynx is more anterior than in an adult

      Explanation:

      In the neonatal stage, the tongue is usually large and comes to the normal size at the age of 1 year. The vocal cords lie inverse C4 and as it reaches the grown-up position inverse C5/6 by the age of 4 (not 1 year).

      Due to the immature cricoid cartilage, the larynx lies more anterior in newborn children. That’s why the cricoid ring is the narrowest part of the paediatric respiratory tract, while in the adults the tightest portion of the respiratory route is vocal cords. The epiglottis is generally expansive and slants at a point of 45 degrees to the laryngeal opening.

      The carina is the ridge of the cartilage in the trachea at the level of T2 in newborn (T4 in adults), that separates the openings of right and left main bronchi.

      Neonates have a comparatively low number of alveoli and then this number gradually increases to a most extreme by the age of 8 (not 3 years).

      Neonates are obligatory nose breathers and any hindrance can cause respiratory issues (e.g., choanal atresia).

    • This question is part of the following fields:

      • Physiology
      0
      Seconds
  • Question 14 - A randomized study aimed at finding out the efficacy of a novel anticoagulant,...

    Incorrect

    • A randomized study aimed at finding out the efficacy of a novel anticoagulant, in preventing stroke in patients suffering from atrial fibrillation, relative to those already available in the market was performed. A 59 year old woman volunteered for it and was randomised to the treatment arm. A year later, following findings were reported:

      165 out of 1050 patients who were prescribed the already prevalent medicine had a stroke while the number of patients who had a single stroke after using the new drug was 132 out of 1044.

      In order to avoid one stroke case, what is the number of patients that need to be treated?

      Your Answer:

      Correct Answer: 32

      Explanation:

      Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.

      It can be found as:

      NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).

      where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)

      So,

      ARR= (165/1050)-(132/1044)

      ARR= (0.157-0.126)

      ARR= 0.031

      NNT= 1/0.031

      NNT=32.3

    • This question is part of the following fields:

      • Statistical Methods
      0
      Seconds
  • Question 15 - Which of the following derived SI units is correctly expressed as their base...

    Incorrect

    • Which of the following derived SI units is correctly expressed as their base units?

      Your Answer:

      Correct Answer: Volt: m2.kg.s-3.A-1

      Explanation:

      The following units are derived SI units of measurement.

      Energy or work: kg.m2.s-2
      The Joule (J) is the energy transferred to an object when a force of one newton acts on that object in the direction of its motion through a distance of one meter or N.m.

      Power: kg.m2.s-3
      The Watt (W) = rate of transfer of energy or Joule per second J/s.

      Force: kg.m.s-2
      One Newton (N) which is the international unit of measure for force = 1 kilogram meter per second squared. 1 Newton of force is the force required to accelerate an object with a mass of 1 kilogram 1 meter per second per second.

      Volt: kg.m2.s-3.A-1
      The volt (V) is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power or W/A.

      Pressure: kg.m-1.s-2
      A pascal (Pa) is force per unit area or N/m2.

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 16 - From the following statements, which is true of humidification? ...

    Incorrect

    • From the following statements, which is true of humidification?

      Your Answer:

      Correct Answer: Ultrasonic humidifier can achieve greater than 100% relative humidity

      Explanation:

      Increasing temperature increases the amount of water vapour contained in air; for example, at 20°C, air contains about 17 g/m3, and at 37°C, air contains about 44 g/m3. The wet and dry bulb hygrometer, like the hair hygrometer, measures relative humidity.

      Under normal operating conditions, Heat and moisture exchangers (HMEs) allows relative humidity of up to 70% to be achieved. Mucus can impair their performance, and they should not be used for longer than 24 hours.

      Hot water bath humidifiers might cause scalding, condensed water in the tubing can interfere with gas flow, and there is a danger of infection.

      The ultrasonic humidifier operates at roughly 2 MHz and may attain relative humidity levels much above 100%.

    • This question is part of the following fields:

      • Anaesthesia Related Apparatus
      0
      Seconds
  • Question 17 - Out of the following, which anatomical structure lies within the spiral groove of...

    Incorrect

    • Out of the following, which anatomical structure lies within the spiral groove of the humerus?

      Your Answer:

      Correct Answer: Radial nerve

      Explanation:

      The shaft of the humerus has two prominent features:
      1. Deltoid tuberosity – attachment for the deltoid muscle
      2. Radial or spiral groove – The radial nerve and profunda brachii artery lie in the groove

      Mid-shaft fractures of the humerus usually occur after a direct blow to the upper arm, which can occur after a fall or RTAs. The most important clinical significance of a mid-shaft humeral fracture is an injury to the radial nerve. The radial nerve originates from the brachial plexus and has roots of C5-T1. It crosses the spiral groove on the posterior side of the shaft of the humerus.
      On examination, the patient may have a wrist drop, loss or weakness of finger extension, and decreased or absent sensation to the posterior forearm, digits 1 to 3, and the radial half of the fourth digit.

      The following parts of the humerus are in direct contact with the indicated
      nerves:
      Surgical neck: axillary nerve.
      Radial groove: radial nerve.
      Distal end of humerus: median nerve.
      Medial epicondyle: ulnar nerve.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 18 - A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

    He has chronic...

    Incorrect

    • A 72-year-old long-term rheumatoid arthritis patient is having shoulder replacement surgery.

      He has chronic obstructive pulmonary disease with a limited exercise tolerance. He agrees to the procedure being performed with an interscalene brachial plexus block.

      Which of the following neurological complications puts this patient at the greatest risk?

      Your Answer:

      Correct Answer: Phrenic nerve block

      Explanation:

      An ipsilateral phrenic nerve block will result from a successful interscalene block (ISB).

      The phrenic nerve is the diaphragm’s sole motor supply, and ipsilateral hemidiaphragmatic paresis affects up to 100% of patients who receive ISBs. Phrenic nerve palsy is usually well tolerated and goes unnoticed by healthy people. However, forced vital capacity decreases by approximately 25%, which can produce ventilatory compromise in patients with limited pulmonary reserve, requiring assisted ventilation.

      Vocal cord palsy occurs when the recurrent laryngeal nerve is inadvertently blocked, causing hoarseness and possibly acute respiratory insufficiency. Unless bilateral laryngeal nerve palsy occurs, which can cause severe laryngeal obstruction, this complication is usually of little consequence.

      ISB can also cause cranial nerve X and XII palsy (Tapia’s syndrome). One-sided cord paralysis, aphonia, and the patient’s tongue deviating toward the block’s side are all symptoms.

      When a local anaesthetic spreads to the stellate ganglion and its cervical sympathetic nerves, Horner’s syndrome can develop. Ptosis of the eyelid, miosis, and anhidrosis of the face are all symptoms. Horner’s syndrome, on the other hand, may not indicate that the brachial plexus is sufficiently blocked.

    • This question is part of the following fields:

      • Pathophysiology
      0
      Seconds
  • Question 19 - A 39-year-old woman, is scheduled for a thyroidectomy for her previously diagnosed Grave's...

    Incorrect

    • A 39-year-old woman, is scheduled for a thyroidectomy for her previously diagnosed Grave's disease. She is eligible for surgery as medical treatment options have failed to control her symptoms and she is the sole guardian for her young children, so radioiodine treatment is unsuitable. While gaining her consent for the surgery, she is told of possible complications of thyroidectomy, which include damage to the sensory branch of the superior laryngeal nerve.

      What is the name of the sensory nerve that arises from the superior laryngeal nerve?

      Your Answer:

      Correct Answer: Internal laryngeal nerve

      Explanation:

      The superior laryngeal nerve gives off two branches: the sensory branch which is the internal laryngeal nerve, and the motor branch which is the external laryngeal nerve.

      The recurrent laryngeal nerve (RLN) rises from the vagus nerve which supplies the intrinsic muscles of the larynx, except the cricothyroid muscles.

    • This question is part of the following fields:

      • Anatomy
      0
      Seconds
  • Question 20 - Which of the following statements is true regarding drug dose and response? ...

    Incorrect

    • Which of the following statements is true regarding drug dose and response?

      Your Answer:

      Correct Answer: Intrinsic activity determines maximal response

      Explanation:

      There are two types of drug dose-response relationships, namely, the graded dose-response and the quantal dose-response relationships.

      Drug response curves are plotted as percentage response again LOG drug concentration. This graph is sigmoid in shape.

      Agonists are drugs with high affinity and high intrinsic activity. Meanwhile, the antagonist is a drug with high affinity but no intrinsic activity. Intrinsic activity determines the maximal response. The maximal response can be achieved even by activation of a small proportion of receptor sites.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 21 - Which of the following statements is true regarding Adrenaline or Epinephrine? ...

    Incorrect

    • Which of the following statements is true regarding Adrenaline or Epinephrine?

      Your Answer:

      Correct Answer: Stimulates ACTH secretion

      Explanation:

      Adrenaline is released by the adrenal glands, acts on ? 1 and 2, ? 1 and 2 receptors, and is responsible for fight or flight response.

      It acts on ? 2 receptors in skeletal muscle vessels-causing vasodilation.

      It acts on ? adrenergic receptors to inhibit insulin secretion by the pancreas. It also stimulates glycogenolysis in the liver and muscle, stimulates glycolysis in muscle.

      It acts on ? adrenergic receptors to stimulate glucagon secretion in the pancreas
      It also stimulates Adrenocorticotrophic Hormone (ACTH) and stimulates lipolysis by adipose tissue

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 22 - Very large SI units are easily expressed using mathematical prefixes.

    One terabyte is equal...

    Incorrect

    • Very large SI units are easily expressed using mathematical prefixes.

      One terabyte is equal to which of the following numbers?

      Your Answer:

      Correct Answer: 1,000,000,000,000 bytes

      Explanation:

      To denote large measured units, the following SI mathematical prefixes are used:

      1 deca = 10 bytes (101)
      1 hecto (h) = 100 bytes
      1 kilo (k)= 1,000 bytes
      1 mega (M) = 1,000,000 bytes
      1 giga (G) = 1,000,000,000 bytes
      1 Tera (T) = 1,000,000,000,000 bytes
      1 Peta (P) = 1,000,000,000,000,000 bytes

    • This question is part of the following fields:

      • Basic Physics
      0
      Seconds
  • Question 23 - Following are some examples of induction agents. Which one has the longest elimination...

    Incorrect

    • Following are some examples of induction agents. Which one has the longest elimination half-life?

      Your Answer:

      Correct Answer: Thiopental

      Explanation:

      Thiopental has the longest elimination half-life of 6-15 hours.

      Elimination half-life of other drugs are given as:
      – Propofol: 5-12 h
      – Methohexitone: 3-5 h
      – Ketamine: 2 h
      – Etomidate: 1-4 h

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 24 - An 82-year old male has shortness of breath which is made worse when...

    Incorrect

    • An 82-year old male has shortness of breath which is made worse when he lies down but investigations have revealed a normal ejection fraction. Why might this be?

      Your Answer:

      Correct Answer: He has diastolic dysfunction

      Explanation:

      Decreased stroke volume causes decreased ejection fraction which results in diastolic dysfunction.
      Ejection fraction is not a useful measure in someone with diastolic dysfunction because stroke volume may be reduced whilst end-diastolic volume may be reduced.
      Diastolic dysfunction may arise with reduced heart compliance.

      Ejection fraction measures of the proportion of blood leaving the ventricles with each beat and is calculated as follows:
      Stroke volume / end-diastolic volume.

      A healthy ejection fraction is usually taken as 60% (based on a stroke volume of 70ml and end-diastolic volume of 120ml).

      Respiratory inspiration causes a decreased pressure in the thoracic cavity, which in turn causes more blood to flow into the atrium.

      Sitting up decreases venous because of the action of gravity on blood in the venous system.
      Hypotension also decreases venous return.
      A less compliant aorta, like in aortic stenosis increases end systolic left ventricular volume which decreases stroke volume.

      Systemic vascular resistance = mean arterial pressure / cardiac output.
      Increased vascular resistance impedes the flow of blood back to the heart.

      Increased venous return increases end diastolic LV volume as there is more blood returning to the ventricles.

    • This question is part of the following fields:

      • Physiology And Biochemistry
      0
      Seconds
  • Question 25 - An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old...

    Incorrect

    • An inguinal hernia repair under general anaesthesia is scheduled for a fit 36-year-old man (75 kg). For perioperative and postoperative analgesia, you decide to perform an inguinal field block.

      Which of the following local anaesthetic solutions is the most appropriate?

      Your Answer:

      Correct Answer: 30 mL bupivacaine 0.5%

      Explanation:

      Perioperative and postoperative analgesia can both be provided by an inguinal hernia field block. The Iliohypogastric and ilioinguinal nerves, as well as the skin, superficial fascia, and deeper structures, must be blocked for maximum effectiveness. The local anaesthetic should ideally have a long duration of action, be highly concentrated, and have a volume of at least 30 mL.

      Plain bupivacaine has a maximum safe dose of 2 mg/kg body weight.

      Because the patient weighs 75 kg, 150 mg bupivacaine can be safely administered. Both 30 mL 0.5 percent bupivacaine (150 mg) and 60 mL 0.25 percent bupivacaine (150 mg) are acceptable doses, but 30 mL 0.5 percent bupivacaine represents the optimal volume and strength, potentially providing a denser and longer block.

      The maximum safe dose of plain lidocaine has been estimated to be between 3.5 and 5 mg/kg. The patient weighs 75 kg and can receive a maximum of 375 mg using the higher dosage regimen:

      There are 200 mg of lidocaine in 10 mL of 2% lidocaine (and therefore 11 mL contains 220 mg)
      200 mg of lidocaine is contained in 20 mL of 1% lidocaine.

      While alternatives are available, Although the doses of 11 mL lidocaine 2% and 20 mL lidocaine 1% are well within the dose limit, the volumes used are insufficient for effective field block for this surgery.

      With 1 in 200,000 epinephrine, the maximum safe dose of lidocaine is 7 mg/kg. The patient can be given 525 mg in this case. Even with epinephrine, 60 mL of 1% lidocaine is 600 mg, which could be considered an overdose.

    • This question is part of the following fields:

      • Pharmacology
      0
      Seconds
  • Question 26 - A 68-year-old man has suffered a myocardial infarction. He has a heart rate...

    Incorrect

    • A 68-year-old man has suffered a myocardial infarction. He has a heart rate of 40 beats per minute currently.
      Your senior attending explains that the slow heart rate is due to the damage to the conduction pathways between the sinoatrial and atrioventricular nodes. His ventricles are being paced by the AV node alone.

      What artery supplies the AV node in the majority of patients?

      Your Answer:

      Correct Answer: Right coronary artery

      Explanation:

      The AV node has an intrinsic firing rate of 40-60 beats per minute which is clinically significant in cases of damage to the conducting pathways as patients continue to have a ventricular rate of 40-60. Patients who have an AV node supplied by the right coronary are said to be right dominant. The remaining 10% are left dominant and supplied by the left circumflex.

      The right coronary artery supplies the right atrium, right ventricle, interatrial septum, and the inferior posterior third of the interventricular septum. It also supplies the atrioventricular node + sinoatrial node in most patients. The posterior descending artery supplies the posterior third of the interventricular septum.

      The heart receives blood supply from coronary arteries. The right and left coronary arteries branch off the aorta and supply oxygenated blood to all heart muscle parts.

      The left main coronary artery branches into:
      1. Circumflex artery – supplies the left atrium, side, and back of the left ventricle. The left marginal artery arises from the left circumflex artery. It travels along the obtuse margin of the heart.
      The left marginal artery, a branch of the circumflex artery, supplies the left ventricle.
      2. Left Anterior Descending (LAD) artery – supplies the front and bottom of the left ventricle and front of the interventricular septum

      The right coronary artery branches into:
      1. Right marginal artery
      2. Posterior descending artery

    • This question is part of the following fields:

      • Anatomy
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  • Question 27 - A 27-year-old woman takes part in a study looking into the effects of...

    Incorrect

    • A 27-year-old woman takes part in a study looking into the effects of different dietary substrates on metabolism. She receives a 24-hour ethyl alcohol infusion.

      A constant volume, closed system respirometer is used to measure CO2 production and consumption. The production of carbon dioxide is found to be 200 mL/minute.

      Which of the following values most closely resembles her anticipated O2 consumption at the conclusion of the trial?

      Your Answer:

      Correct Answer: 300 mL/minute

      Explanation:

      The respiratory quotient (RQ) is the ratio of CO2 produced by the body to O2 consumed in a given amount of time.

      CO2 produced / O2 consumed = RQ

      CO2 is produced at a rate of 200 mL per minute, while O2 is consumed at a rate of 250 mL per minute. An RQ of around 0.8 is typical for a mixed diet.

      The RQ will change depending on the energy substrates consumed in the diet. Granulated sugar is a refined carbohydrate that contains 99.999 percent carbohydrate and no lipids, proteins, minerals, or vitamins.

      Glucose and other hexose sugars (glucose and other hexose sugars):
      RQ=1

      Fats:
      RQ = 0.7

      Proteins:
      Approximately 0.9 RQ

      Ethyl alcohol is a type of alcohol.

      200/300 = 0.67 RQ

      For complete oxidation, lipids and alcohol require more oxygen than carbohydrates.

      When carbohydrate is converted to fat, the RQ can rise above 1.0. Fat deposition and weight gain are likely to occur in these circumstances.

    • This question is part of the following fields:

      • Physiology
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  • Question 28 - An older woman has been brought into the emergency department with symptoms of...

    Incorrect

    • An older woman has been brought into the emergency department with symptoms of a stroke. A CT angiogram is performed for diagnosis, which displays narrowing in the artery that supplies the right common carotid. Which of the following artery is the cause of stroke in this patient?

      Your Answer:

      Correct Answer: Brachiocephalic artery

      Explanation:

      The arch of aorta gives rise to three main branches:
      1. Brachiocephalic artery
      2. Left common carotid artery
      3. Left subclavian artery

      The brachiocephalic artery then gives rise to the right subclavian artery and the right common carotid artery.

      The right common carotid artery arises from the brachiocephalic trunk posterior to the sternoclavicular joint.

      The coeliac trunk is a branch of the abdominal aorta.
      The ascending aorta supplies the coronary arteries.

    • This question is part of the following fields:

      • Anatomy
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  • Question 29 - A 68-year-old man is to be operated.
     
    His past history is significant for a...

    Incorrect

    • A 68-year-old man is to be operated.
       
      His past history is significant for a stroke, and some residual neurological deficit. The cranial nerves are examined clinically. He is unable to rotate his head to the left side when resistance is applied. Moreover, there is tongue wasting on the right side. There are no unusual sensory signs and symptoms.

      The most likely reason for these clinical findings is?

      Your Answer:

      Correct Answer: Damage to hypoglossal (XII) and spinal accessory (XI) nerves

      Explanation:

      The upper five cervical segments of the spinal cord give rise to the XI cranial nerve. They connect with a few smaller branches before exiting the skull through the jugular foramen. The sternomastoid and trapezius muscles get their motor supply from the accessory root. Except for the palatoglossus, the hypoglossal nerve supplies motor supply to all tongue muscles.

      The inability to shrug the shoulder on the affected side and rotate the head to the side against resistance is caused by damage to the spinal accessory nerve. This is due to the trapezius and sternomastoid muscles’ weakness.

      The hypoglossal nerve is damaged, resulting in tongue wasting and inability to move from side to side.

      The stylopharyngeus receives motor supply from the glossopharyngeal nerve. It also carries taste sensory fibres from the back third of the tongue, as well as the carotid sinus, carotid body, pharynx, and middle ear.

      Motor supply to the larynx, pharynx, and palate; parasympathetic innervation to the heart, lung, and gut; and sensory fibres from the epiglottis and valleculae are all provided by the vagus nerve.

    • This question is part of the following fields:

      • Pathophysiology
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  • Question 30 - The leading cause of perioperative anaphylaxis per hundred thousand administrations is? ...

    Incorrect

    • The leading cause of perioperative anaphylaxis per hundred thousand administrations is?

      Your Answer:

      Correct Answer: Teicoplanin

      Explanation:

      The leading cause of perioperative anaphylaxis in the UK currently are antibiotics. They account for 46% of cases with identified causative agents. Co-amoxiclav and teicoplanin between them account for 89% of antibiotic-induced perioperative anaphylaxis

      Neuromuscular blocking agents (NMBAs) are the second leading cause and account for 33% of case.

      Chlorhexidine (0.78/100,000 administrations)
      Co-amoxiclav (8.7/100,000 administrations)Suxamethonium (11.1/100,000 administrations)
      Patent blue dye (14.6/100,000 administrations)
      Teicoplanin (16.4/100,000 administrations)

      Anaphylaxis to chlorhexidine periop poses a significant risk in the healthcare setting because of its widespread use with some being fatal.

    • This question is part of the following fields:

      • Pharmacology
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SESSION STATS - PERFORMANCE PER SPECIALTY

Physiology And Biochemistry (1/1) 100%
Pharmacology (0/1) 0%
Anatomy (0/2) 0%
Clinical Measurement (1/2) 50%
Pathophysiology (1/2) 50%
Antomy (0/1) 0%
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