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  • Question 1 - Calculate the total peripheral resistance for a patient with a blood pressure of...

    Incorrect

    • Calculate the total peripheral resistance for a patient with a blood pressure of 130/70 mm HG and cardiac output of 5 litres / min?

      Your Answer: 20 mmHg × min/l

      Correct Answer: 18 mmHg × min/l

      Explanation:

      Total peripheral resistance = Mean arterial pressure/Cardiac output. And the mean arterial pressure = Diastolic pressure + 1/3 (Systolic pressure – Diastolic pressure), i.e., 70 + 1/3 (130-70) = 90 mmHg. Therefore, total peripheral resistance = 90 mmHg/5 l per min = 18 mmHg × min/l.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      99.6
      Seconds
  • Question 2 - Rapid eye movement (REM) sleep is likely to be affected by a lesion...

    Incorrect

    • Rapid eye movement (REM) sleep is likely to be affected by a lesion in the:

      Your Answer: Basal ganglia

      Correct Answer: Pons

      Explanation:

      Rapid eye movement (REM) sleep is also known as paradoxical sleep, as the summed activity of the brain’s neurons is quite similar to that during waking hours. Characterised by rapid movements of the eyes, most of the vividly recalled dreams occur during this stage of sleep. The total time of REM sleep for an adult is about 90–120 min per night.

      Certain neurones in the brainstem, known as REM sleep-on cells, which are located in the pontine tegmentum, are particularly active during REM sleep and are probably responsible for its occurrence. The eye movements associated with REM are generated by the pontine nucleus with projections to the superior colliculus and are associated with PGO (pons, geniculate, occipital) waves.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      27.7
      Seconds
  • Question 3 - Calculate the stroke volume in a patient admitted for coronary bypass surgery, with...

    Incorrect

    • Calculate the stroke volume in a patient admitted for coronary bypass surgery, with the following parameters pre-operatively:

      Oxygen consumption = 300 ml/min

      Arterial oxygen content = 20 ml/100 ml blood

      Pulmonary arterial oxygen content = 15 ml/100 ml blood and Heart rate = 100 beats/min.

      Your Answer: 40 ml

      Correct Answer: 60 ml

      Explanation:

      By Fick’s principle, cardiac output can be calculated as follows: VO2 = CO × (CAO2– CVO2) where VO2= oxygen consumption, CO = cardiac output, CAO2 = arterial oxygen content and CvO2 = mixed venous oxygen content. Thus, in the given problem, 300 ml/min = CO × (20 – 15) ml/100 ml CO = 300 × 100/5 ml/min CO = 6000 ml/min. Also, cardiac output = stroke volume × heart rate. Thus, 6000 ml/min = stroke volume × 100 beats/min. Hence, stroke volume = 6000/100 ml/min which is 60 ml/min.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      119.1
      Seconds
  • Question 4 - A child defecates a few minutes after being fed by the mother. This...

    Incorrect

    • A child defecates a few minutes after being fed by the mother. This is most likely due to:

      Your Answer: Enterocolic reflex

      Correct Answer: Gastrocolic reflex

      Explanation:

      The gastrocolic reflex is a physiological reflex that involves increase in colonic motility in response to stretch in the stomach and by-products of digestion in the small intestine. It is shown to be uneven in its distribution throughout the colon, with the sigmoid colon affected more than the right side of the colon in terms of a phasic response. Various neuropeptides have been proposed as mediators of this reflex, such as serotonin, neurotensin, cholecystokinin and gastrin.

    • This question is part of the following fields:

      • Gastroenterology
      • Physiology
      24.5
      Seconds
  • Question 5 - Which of the following will be affected by a lesion in the posterior...

    Correct

    • Which of the following will be affected by a lesion in the posterior column-medial lemniscus system?

      Your Answer: Fine touch

      Explanation:

      The posterior column–medial lemniscus (PCML) pathway is a sensory pathway that transmits fine touch and conscious proprioceptive information from the body to the brain. As the posterior columns are also known as dorsal columns, the pathway is also called the dorsal column–medial lemniscus system or DCML.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      16.3
      Seconds
  • Question 6 - A 56-year-old woman weighs 75 kg. In this patient, total body water, intracellular...

    Incorrect

    • A 56-year-old woman weighs 75 kg. In this patient, total body water, intracellular fluid and extracellular fluid are respectively:

      Your Answer: 45 l, 35 l, 10 l

      Correct Answer: 45 l, 30 l, 15 l

      Explanation:

      The percentages of body water contained in various fluid compartments add up to total body water (TBW). This water makes up a significant fraction of the human body, both by weight and by volume. The total body water (TBW) content of humans is approximately 60% of body weight. Two-thirds is located in the intracellular and one-third in the extracellular compartment. So, in a 75-kg individual, TBW = 60 × 75/100 = 45 l. Intracellular content = 2/3 × 45 = 30 l and extracellular content = 1/3 × 45 = 15 l.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      92.4
      Seconds
  • Question 7 - A 77-year-old woman's renal function is tested. The following results were obtained during...

    Incorrect

    • A 77-year-old woman's renal function is tested. The following results were obtained during a 24-h period:

      Urine flow rate: 2. 0 ml/min

      Urine inulin: 0.5 mg/ml

      Plasma inulin: 0.02 mg/ml

      Urine urea: 220 mmol/l

      Plasma urea: 5 mmol/l.

      What is the urea clearance?

      Your Answer: 4.4 ml/min

      Correct Answer: 88 ml/min

      Explanation:

      Urea is reabsorbed in the inner medullary collecting ducts of the nephrons. The clearance (C) of any substance can be calculated as follows: C = (U × V)/P, where U and P are the urine and plasma concentrations of the substance, respectively and V is the urine flow rate. So, glomerular filtration rate = (0.220 × 2. 0)/0.005 = 88 ml/min.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      55.8
      Seconds
  • Question 8 - Extracellular body fluid as compared with intracellular body fluid: ...

    Incorrect

    • Extracellular body fluid as compared with intracellular body fluid:

      Your Answer: Has lower tonicity

      Correct Answer: Is relatively rich in glucose

      Explanation:

      The percentages of body water contained in various fluid compartments add up to total body water (TBW). This water makes up a significant fraction of the human body, both by weight and by volume. Ensuring the right amount of body water is part of fluid balance, an aspect of homeostasis. The extracellular fluid (ECF) includes all fluids outside the cells. This fluid can be divided into three fluid departments: interstitial (in the tissue spaces) fluid, blood plasma and lymph, and specialised compartments called transcellular fluid. The extracellular fluid surrounds all the cells in the body and is in equilibrium with the intracellular fluid. So, its composition must remain fairly constant even though substances are passing into and out of the cells. The interstitial fluid, though called a fluid, is in a reality a gel-like composition made up of: water, proteoglycan molecules and collagen. The extracellular fluid constitutes 40% of total body water, with intracellular fluid making up the remaining 60%. It is relatively rich in glucose.

    • This question is part of the following fields:

      • Fluids & Electrolytes
      • Physiology
      30.8
      Seconds
  • Question 9 - A patient admitted for esophagectomy showed low levels of the lightest plasma protein...

    Incorrect

    • A patient admitted for esophagectomy showed low levels of the lightest plasma protein in terms of weight. Which of the following is the lightest plasma protein:

      Your Answer: Gamma-globulin

      Correct Answer: Albumin

      Explanation:

      Albumin is the most abundant and the lightest of all the plasma proteins. It maintains osmotic pressure, transports unconjugated bilirubin, thyroid hormones, fatty acids, drugs and acts as a buffer for pH.

    • This question is part of the following fields:

      • General
      • Physiology
      656.2
      Seconds
  • Question 10 - Which of the following is a true statement regarding the pupil? ...

    Incorrect

    • Which of the following is a true statement regarding the pupil?

      Your Answer: Pupil diameter is determined by the balance between parasympathetic tone to the radial fibres of the iris and sympathetic tone to the pupillary sphincter muscle.

      Correct Answer: Phentolamine causes pupil constriction

      Explanation:

      A balance between the sympathetic tone to the radial fibres of the iris and parasympathetic tone to the pupillary sphincter muscle determines the pupil size. Phentolamine (α-adrenergic receptor blocker) causes pupillary constriction. Dilatation of the pupil occurs with increased sympathetic activity, decreased parasympathetic activity during darkness or block of muscarinic receptors by atropine.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      58.4
      Seconds
  • Question 11 - Gastric acid secretion is stimulated by which of the following? ...

    Correct

    • Gastric acid secretion is stimulated by which of the following?

      Your Answer: Gastrin

      Explanation:

      Gastric acid secretion is stimulated by three factors:

      – Acetylcholine, from parasympathetic neurones of the vagus nerve that innervate parietal cells directly

      – Gastrin, produced by pyloric G-cells

      – Histamine, produced by mast cells.

      Gastric acid is inhibited by three factors:

      – Somatostatin

      – Secretin

      – Cholecystokinin

    • This question is part of the following fields:

      • Endocrine
      • Physiology
      10.9
      Seconds
  • Question 12 - Myoglobin is released as a result of rhabdomyolysis from damaged skeletal muscles. What...

    Correct

    • Myoglobin is released as a result of rhabdomyolysis from damaged skeletal muscles. What function do they perform in the muscle?

      Your Answer: Acts like haemoglobin and binds with O2

      Explanation:

      Myoglobin is a pigmented globular protein made up of 153 amino acids with a prosthetic group containing haem around which the apoprotein folds. It is the primary oxygen carrying protein of the muscles. The binding of oxygen to myoglobin is unaffected by the oxygen pressure as it has an instant tendency to bind given its hyperbolic oxygen curve. It releases oxygen at very low pO2 levels.

    • This question is part of the following fields:

      • General
      • Physiology
      69.8
      Seconds
  • Question 13 - Hormones of the anterior pituitary include which of the following? ...

    Correct

    • Hormones of the anterior pituitary include which of the following?

      Your Answer: Prolactin

      Explanation:

      The anterior pituitary gland (adenohypophysis or pars distalis) synthesizes and secretes:

      1. FSH (follicle-stimulating hormone)

      2. LH (luteinizing hormone)

      3. Growth hormone

      4. Prolactin

      5. ACTH (adrenocorticotropic hormone)

      6. TSH (thyroid-stimulating hormone).

      The posterior pituitary gland (neurohypophysis) stores and secretes 2 hormones produced by the hypothalamus:

      1. ADH (antidiuretic hormone or vasopressin)

      2. Oxytocin

    • This question is part of the following fields:

      • Endocrine
      • Physiology
      86.4
      Seconds
  • Question 14 - Glucose is the most important source of energy for cellular respiration. The transport...

    Incorrect

    • Glucose is the most important source of energy for cellular respiration. The transport of glucose in the renal tubular cells occurs via:

      Your Answer: Secondary active transport with potassium

      Correct Answer: Secondary active transport with sodium

      Explanation:

      In 1960, Robert K. Crane presented for the first time his discovery of the sodium-glucose cotransport as the mechanism for glucose absorption. Glucose transport through biological membranes requires specific transport proteins. Transport of glucose through the apical membrane of renal tubular as well as intestinal epithelial cells depends on the presence of secondary active Na+–glucose symporters, SGLT-1 and SGLT-2, which concentrate glucose inside the cells, using the energy provided by co-transport of Na+ ions down their electrochemical gradient.

    • This question is part of the following fields:

      • Physiology
      • Renal
      27.2
      Seconds
  • Question 15 - The neurotransmitters adrenaline, noradrenaline and dopamine are derived from which amino acid? ...

    Incorrect

    • The neurotransmitters adrenaline, noradrenaline and dopamine are derived from which amino acid?

      Your Answer: Tryptophan

      Correct Answer: Tyrosine

      Explanation:

      Tyrosine is the precursor to adrenaline, noradrenaline and dopamine. Tyrosine hydroxylase converts tyrosine to DOPA, which is in turn converted to dopamine, then to noradrenaline and finally adrenaline.

    • This question is part of the following fields:

      • Endocrine
      • Physiology
      10.1
      Seconds
  • Question 16 - Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the...

    Incorrect

    • Signals pass through neuromuscular junctions via the neurotransmitter acetylcholine. After release from the skeletal neuromuscular junction, acetylcholine:

      Your Answer:

      Correct Answer: Causes postsynaptic depolarisation

      Explanation:

      Acetylcholine is released from the presynaptic membrane into the cleft where it binds to the ion gated channels on the post synaptic membrane, causing them to open. This results in sodium entering into the fibre and further depolarizing it, creating an action potential.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 17 - Whilst snorkelling, a 30-year old gentleman has the respiratory rate of 10/min, tidal...

    Incorrect

    • Whilst snorkelling, a 30-year old gentleman has the respiratory rate of 10/min, tidal volume of 550 ml and an effective anatomical dead space of 250 ml. What is his alveolar ventilation?

      Your Answer:

      Correct Answer: 3000 ml/min

      Explanation:

      Alveolar ventilation is the amount of air reaching the alveoli per minute. Alveolar ventilation = respiratory rate × (tidal volume – anatomical dead space volume). Thus, alveolar ventilation = 10 × (550 − 250) = 3000 ml/min.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      0
      Seconds
  • Question 18 - When one is silently counting, what part of his brain will show increased...

    Incorrect

    • When one is silently counting, what part of his brain will show increased regional cerebral blood flow (rCBF)?

      Your Answer:

      Correct Answer: Supplementary motor area

      Explanation:

      Regional cerebral blood flow (rCBF) increases in the superior speech cortex (supplementary motor area) during periods of silent counting, whereas speaking aloud will do so in the motor cortex and medial temporal lobe, along with the superior speech cortex.

    • This question is part of the following fields:

      • Neurology
      • Physiology
      0
      Seconds
  • Question 19 - During a normal respiratory exhalation, what is the recoil alveolar pressure? ...

    Incorrect

    • During a normal respiratory exhalation, what is the recoil alveolar pressure?

      Your Answer:

      Correct Answer: +10 cmH2O

      Explanation:

      To determine compliance of the respiratory system, changes in transmural pressures (in and out) immediately across the lung or chest cage (or both) are measured simultaneously with changes in lung or thoracic cavity volume. Changes in lung or thoracic cage volume are determined using a spirometer with transmural pressures measured by pressure transducers. For the lung alone, transmural pressure is calculated as the difference between alveolar (pA; inside) and intrapleural (ppl; outside) pressure. To calculate chest cage compliance, transmural pressure is ppl (inside) minus atmospheric pressure (pB; outside). For the combined lung–chest cage, transmural pressure or transpulmonary pressure is computed as pA – pB. pA pressure is determined by having the subject deeply inhale a measured volume of air from a spirometer. Under physiological conditions the transpulmonary or recoil pressure is always positive; intrapleural pressure is always negative and relatively large, while alveolar pressure moves from slightly negative to slightly positive as a person breathes.

    • This question is part of the following fields:

      • Physiology
      • Respiratory
      0
      Seconds
  • Question 20 - A 30 year old female presented in the emergency with an irregular pulse....

    Incorrect

    • A 30 year old female presented in the emergency with an irregular pulse. Her ECG showed absent P-waves with irregular RR interval. What is the most likely diagnosis?

      Your Answer:

      Correct Answer: Atrial fibrillation

      Explanation:

      Atrial fibrillation is one of the most common cardiac arrhythmias. It is often asymptomatic but may present with symptoms of palpitations, fainting, chest pain and heart failure. Characteristic findings are: absence of P-waves, unorganised electrical activity in their place, irregularity of RR interval due to irregular conduction of impulses to the ventricles and if paroxysmal AF is suspected, episodes may be documented with the use of Holter monitoring

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 21 - A 47 year-old woman was admitted for elective cholecystectomy, with a past...

    Incorrect

    • A 47 year-old woman was admitted for elective cholecystectomy, with a past history of easy bruising and heavy menstrual periods. The patient was also diagnosed with Willebrand's disease. Willebrand's disease is:

      Your Answer:

      Correct Answer: Autosomal dominant

      Explanation:

      von Willebrand disease is an autosomal dominant disorder marked by the deficiency of vWF, a large protein synthesized by the endothelial cells and megakaryocytes. It mediates adhesion of platelets to the subendothelium at site of vascular injury. Disease characteristics include impaired platelet adhesion, prolonged bleeding time and a functional deficiency of factor VIII (vWF is its carrier protein).

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 22 - Renin is secreted by pericytes in the vicinity of the afferent arterioles of the...

    Incorrect

    • Renin is secreted by pericytes in the vicinity of the afferent arterioles of the kidney from the juxtaglomerular cells. Plasma renin levels are decreased in patients with:

      Your Answer:

      Correct Answer: Primary aldosteronism

      Explanation:

      Primary aldosteronism, also known as primary hyperaldosteronism or Conn’s syndrome, is excess production of the hormone aldosterone by the adrenal glands resulting in low renin levels. Most patients with primary aldosteronism (Conn’s syndrome) have an adrenal adenoma. The increased plasma aldosterone concentration leads to increased renal Na+ reabsorption, which results in plasma volume expansion. The increase in plasma volume suppresses renin release from the juxtaglomerular apparatus and these patients usually have low plasma renin levels. Salt restriction and upright posture decrease renal perfusion pressure and therefore increases renin release from the juxtaglomerular apparatus. Secondary aldosteronism is due to elevated renin levels and may be caused by heart failure or renal artery stenosis.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds
  • Question 23 - Atractyloside is an inhibitor of electron transport chain. It is expected to have...

    Incorrect

    • Atractyloside is an inhibitor of electron transport chain. It is expected to have little or no effect on the functioning of which of the following cell types?

      Your Answer:

      Correct Answer: Red blood cells

      Explanation:

      Electron transport chain is a series of electron carriers that are embedded in the mitochondrial membrane. It is the place where ATP is made. Inhibiting the electron transport chain will stop production of ATP. Red blood cells are the only cell in the given option which do not contain ATP.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 24 - When does the heart rate decrease? ...

    Incorrect

    • When does the heart rate decrease?

      Your Answer:

      Correct Answer: Pressure on the eyeball

      Explanation:

      Various vagotonic manoeuvres (e.g. Valsalva manoeuvre, carotid sinus massage, pressure on eyeballs, ice-water facial immersion, swallowing of ice-cold water) result in increased parasympathetic tone through the vagus nerve which results in a decrease in heart rate. These manoeuvres may be clinically useful in terminating supraventricular arrhythmias.

    • This question is part of the following fields:

      • Cardiovascular
      • Physiology
      0
      Seconds
  • Question 25 - In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of...

    Incorrect

    • In the kidney, the macula densa is an area of closely packed specialized cells lining the wall of the:

      Your Answer:

      Correct Answer: Distal convoluted tubule

      Explanation:

      In the kidney, the macula densa is an area of closely packed specialised cells lining the region of the distal convoluted tubule (DCT) lying next to the glomerular vascular pole. The cells of the macula densa are sensitive to the ionic content and water volume of the fluid in the DCT, producing signals that promote renin secretion by other cells of the juxtaglomerular apparatus.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds
  • Question 26 - Which of the following organs is most likely to have dendritic cells? ...

    Incorrect

    • Which of the following organs is most likely to have dendritic cells?

      Your Answer:

      Correct Answer: Skin

      Explanation:

      Dendritic cells are part of the immune system and they function mainly as antigen presenting cells. They are present in small quantities in tissues which are in contact in the external environment. Mainly in the skin and to a lesser extent in the lining of the nose, lungs, stomach and intestines. In the skin they are known as Langerhans cells.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 27 - Action potentials are used extensively by the nervous system to communicate between neurones...

    Incorrect

    • Action potentials are used extensively by the nervous system to communicate between neurones and muscles or glands. What happens during the activation of a nerve cell membrane?

      Your Answer:

      Correct Answer: Sodium ions flow inward

      Explanation:

      During the generation of an action potential, the membrane gets depolarized which cause the voltage gated sodium channels to open and sodium diffuses inside the neuron, resulting in the membrane potential moving towards a positive value. This positive potential will then open the voltage gated potassium channels and cause more K+ to move out decreasing the membrane potential and restoring the membrane potential to its resting value.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 28 - A medical student is told a substance is freely filtered but is not...

    Incorrect

    • A medical student is told a substance is freely filtered but is not metabolised, secreted, or stored in the kidney. It has a plasma concentration of 1000 mg/l and its urine excretion rate is 25 mg/min, and the inulin clearance is 100 ml/min. What is the rate of tubular reabsorption of the substance?

      Your Answer:

      Correct Answer: 75 mg/min

      Explanation:

      Reabsorption or tubular reabsorption is the process by which the nephron removes water and solutes from the tubular fluid (pre-urine) and returns them to the circulating blood. To calculate the reabsorption rate of substance Z we use the following equation: excretion = (filtration + secretion) – reabsorption. As this substance is freely filtered, its filtration rate is equal to that of inulin. So 25 = (100 + 0) – reabsorption. Reabsorption = 100 – 25 therefore reabsorption = 75 mg/min.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds
  • Question 29 - A 50 year old man on warfarin therapy following insertion of a pacemaker...

    Incorrect

    • A 50 year old man on warfarin therapy following insertion of a pacemaker presented with epistaxis. Which of the following is true regarding blood coagulation?

      Your Answer:

      Correct Answer: Patients with haemophilia A usually have a normal bleeding time

      Explanation:

      A prolonged bleeding time is seen in platelet disorders like thrombocytopenia. Patients with haemophilia A or B have a prolonged PTT but not a prolonged bleeding time.

      Ca2+ is necessary for coagulation.

      von Willebrand factor is an important part of the factor VIII complex and promotes platelet adhesion and aggregation.

      DIC results in depleted coagulation factors and accumulation of fibrin.

    • This question is part of the following fields:

      • General
      • Physiology
      0
      Seconds
  • Question 30 - Diuretics that act on the ascending limb of the loop of Henle produce:...

    Incorrect

    • Diuretics that act on the ascending limb of the loop of Henle produce:

      Your Answer:

      Correct Answer: Reduced active transport of sodium

      Explanation:

      The loop of Henlé leads from the proximal convoluted tubule to the distal convoluted tubule. Its primary function uses a counter current multiplier mechanism in the medulla to reabsorb water and ions from the urine. It can be divided into four parts:

      1. Descending limb of loop of Henlé – low permeability to ions and urea, while being highly permeable to water

      2. Thin ascending limb of loop of Henlé – not permeable to water, but it is permeable to ions

      3. Medullary thick ascending limb of loop of Henlé – sodium (Na+), potassium (K+) and chloride (Cl–) ions are reabsorbed by active transport. K+ is passively transported along its concentration gradient through a K+ channel in the basolateral aspect of the cells, back into the lumen of the ascending limb.

      4. The cortical thick ascending limb – the site of action where loop diuretics such as furosemide block the K+/Na+/2Cl− co-transporters = reduced active transport.

    • This question is part of the following fields:

      • Physiology
      • Renal
      0
      Seconds

SESSION STATS - PERFORMANCE PER SPECIALTY

Cardiovascular (0/2) 0%
Physiology (4/15) 27%
Neurology (1/3) 33%
Gastroenterology (0/1) 0%
Fluids & Electrolytes (0/3) 0%
General (1/2) 50%
Endocrine (2/3) 67%
Renal (0/1) 0%
Passmed