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Question 1
Incorrect
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A study of 1500 participants is designed to determine the normal range for a number of parameters in a certain population.
Analysis has revealed that there is a strong positive correlation between height and forced expiratory volume (FEV1).
Which of the following statistical technique can be utilized to predict FEV1 at any given height in this cohort?Your Answer: Forest plot
Correct Answer: Linear regression
Explanation:A forest plot is a graphical representation that summarizes the findings of several research, such as a meta-analysis of a series of randomized controlled trials.
The Kaplan-Meier estimate shows survival over time, for example, plotting the number of patients still alive seven years after chemotherapy for lung cancer.
Fisher’s exact test similarly uses contingency tables to assess statistical significance, however, it is typically used when sample sizes are small.
Chi-square test assesses whether an association exists between two categorical variables using the observed and expected frequencies. For instance, is social class (I-V) related to body mass index (BMI) category? Using the observed and anticipated frequencies, the Chi-square test determines whether a connection exists between two categorical variables. For example, is socio-economic status related to BMI category?
Linear regression is a technique which attempts to model the relationship between two variables by fitting a linear equation to observed data. Linear regression uses correlation between two continuous variables. As correlation only indicates the strength of an association only, it cannot be used to forecast the change in one variable when a second variable is altered.
This equation takes the form y = mx + c, where ‘y’ is the dependent variable, ‘x’ is the independent variable, ‘m’ is the slope of the line and ‘c’ is the intercept. In this example, for a range of heights, it would be possible to map a line of best fit to a scatter plot and thus predict the forced expiratory volume (FEV1) for an individual.
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This question is part of the following fields:
- Statistical Methods
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Question 2
Incorrect
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Which of the following statements is correct about a characteristic that is normally distributed in a population?
Your Answer: Ten percent of individuals will be beyond two standard deviations from the mean
Correct Answer: There will be approximately equal numbers who have more or less of the characteristic than the mean
Explanation:68% of the population will be found in one standard deviation (SD) above plus one SD below the mean. Two SDs above plus two SDs below the mean will include 95% of the population.
The median can be greater or less than the mean as it is simply the mid point of the data after the data is arranged. Half the data are above and half below the median .
The mode is a true score, unlike the mean or the median. It is the most common score or the score obtained from the largest number of subjects in any given data.
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This question is part of the following fields:
- Statistical Methods
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Question 3
Incorrect
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Which among the following is not true regarding disease rates?
Your Answer: Attributable risk is equal to the disease rate in exposed people minus that in unexposed people
Correct Answer: The odds ratio is synonymous with the risk ratio
Explanation:The relative risk (also known as risk ratio [RR]) is the ratio of risk of an event in one group (e.g., exposed group) versus the risk of the event in the other group (e.g., nonexposed group).
The odds ratio (OR) is the ratio of odds of an event in one group versus the odds of the event in the other group.
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This question is part of the following fields:
- Statistical Methods
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Question 4
Incorrect
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A new proton pump inhibitor (PPI) is being evaluated in elderly patients who are taking aspiring. Study designed has 120 patients receiving the PPI, while a control group of 240 individuals is given the standard PPI. Over a span of 6 years, 24 of the group receiving the new PPI had an upper GI bleed compared to 60 individuals who received the standard PPI.
How would you calculate the absolute risk reduction?Your Answer: 10%
Correct Answer: 5%
Explanation:Absolute risk reduction = (Control event rate) – (Experimental event rate)
Experimental event rate = 24 / 120 = 0.2
Control event rate = 60 / 240 = 0.25
Absolute risk reduction = 0.25 – 0.2 = 0.05 = 5% reduction
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This question is part of the following fields:
- Statistical Methods
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Question 5
Incorrect
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A study aimed at assessing the validity of a novel diagnostic test for heart failure is being performed. The curators are worried that not all the patients will get the prevalent gold standard test.
Which type of bias is that?Your Answer: Attention bias
Correct Answer: Work-up bias
Explanation:Work up bias involves comparing the novel diagnostic test with the current standard test. A portion of the patients undergo the standard test while others undergo the new test as the standard test is costly. The result can be alteration in specify and sensitivity.
Selection bias is when randomisation is not achieved.
Attention bias refers to the person’s failure to consider various alternatives when he pre occupied by some other thoughts.
Instrument bias is related to the experience and extent of familiarization of the participating individuals with the test.
Co intervention bias is characterized by the groups receiving different co interventions.
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This question is part of the following fields:
- Statistical Methods
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Question 6
Incorrect
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A graph was plotted after administration of fentanyl infusion to a patient. The following are the x- and y-axis of the graph:
X-axis: Dose of fentanyl
Y-axis: Mu receptor occupancy, measured using positron emission tomography
Given the data above, what would be the best representation of the graph if the data on the x-axis are converted to logarithms?Your Answer: Wash-in exponential curve to a straight line
Correct Answer: Rectangular hyperbola to sigmoid curve
Explanation:The dose-response curve plots the graph of the dose (drug concentration) versus the response. As doses increase, the response increment diminishes; finally, doses may be reached at which no further increase in response can be achieved. This relation between drug concentration and effect is traditionally described by a hyperbolic curve. When the x-axis is plotted in log scale, the graph yields a sigmoid curve.
Efficacy (Emax) and potency (EC50) can be derived from this curve. Emax is the maximal effect achievable, with increasing concentration of a drug. EC50 is the concentration of the drug, wherein half of the maximal effect is achieved.
When the graph is plotted using a log [response/1-response] against log dose, the sigmoid curve becomes a straight line (Hill plot). A graph that transforms from a straight line to exponential curve is mathematically incorrect. A graph that transforms from either a wash-in or wash-out exponential curve to a straight line comes from an initial set of data plotted against time, to a logarithmic transformation of the initial data set against time.
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This question is part of the following fields:
- Statistical Methods
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Question 7
Incorrect
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Provided below is an abstract of a study conducted recently.
A consensus was developed among international experts. A total of 27 experts were invited. 91% of them decided to show up. A systematic review was performed. This comprised of open ended questions and the participants were encouraged to provide suggestions by e-mail. In the second phase google forms were used. Participants were asked to rate survey items on a scale of 5 points. Items that were rated critical by no less than 80% of the experts were included. Items that were rendered important by 65-79% of experts were inducted in the next survey for re rating. Items that were rated below 65% were rejected.
Which of the following methods was used in the study from which the abstract has been taken?Your Answer: Analytic induction
Correct Answer: The Delphi method
Explanation:The process used in the study is Delphi method. This method kicks off with an open ended questionnaire and uses its responses as a survey instrument for the next round in which each of the participants is asked to rate the items that the investigators have summarized on the basis of the data collected in the first round.
Any disagreement is further discussed in phases to come on the basis of information obtained from previous phases.
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This question is part of the following fields:
- Statistical Methods
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Question 8
Incorrect
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Levels of serum potassium in around 1000 patients that were on ACE inhibitor were measured. The mean value was calculated to be 4.6mmol/L and a standard deviation of 0.3mmol/L was recorded.
Which among the given options is correct?Your Answer: 68.3% of values lie between 4.5 and 4.75 mmol/l
Correct Answer: 68.3% of values lie between 4.3 and 4.9 mmol/l
Explanation:Its known that 68.3% of the total values of a normally distributed variable are found within a range of 1 standard deviation from the mean which makes the range to be 4.3 to 4.9 mmol/L.
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This question is part of the following fields:
- Statistical Methods
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Question 9
Incorrect
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A controlled retrospective study's level of evidence is?
Your Answer: Level 2
Correct Answer: Level 3
Explanation:Level 1 – High-quality randomised controlled trial with statistically significant difference or no statistically significant difference but narrow confidence intervals (prospective controlled)
Level 2 – Prospective comparative study (prospective uncontrolled)
Level 3 – Case-control study, retrospective comparative study (retrospective controlled)
Level 4 – Case series (retrospective uncontrolled)
Level 5 – Expert opinion.
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This question is part of the following fields:
- Statistical Methods
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Question 10
Incorrect
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Which of the following bias is more prone to case-control studies?
Your Answer: Omitted-variable bias
Correct Answer: Recall bias
Explanation:Omitted variable bias occurs when a statistician passes over one or more relevant variables from the study.
Publication bias occurs in publish academic research. it occurs when the results of the study effect the decision whether to publish or not.
Expectation bias occurs when the expectation of a researcher about the results effect the behaviour of the participants. Expectations may come from communication and experiences.
Work up bias occurs in the study of diagnostic test validity, whether a gold standard procedure has been used. work up bias can seriously affect the specificity of the test.
Recall bias introduced when participants in a study are systematically more or less likely to recall and relate information on exposure depending on their outcome status. Recall bias is more potential for Case-control studies.
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This question is part of the following fields:
- Statistical Methods
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Question 11
Incorrect
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A double-blinded randomised controlled trial is proposed to assess the effectiveness of a new blood pressure medication.
Which type of bias can be avoided by ensuring the patient and doctor are blinded?Your Answer: Confounding bias
Correct Answer: Expectation bias
Explanation:Observers may subconsciously measure or report data in a way that favours the expected study outcome. Therefore, by blinding the study we can eliminate expectation bias.
Recall bias is a systematic error that occurs when the study participants omit details or do not remember previous events or experiences accurately.
Verification can occur during investigations when there is a difference in testing strategy between groups of individuals, which might lead to biasness due to differing ways of verifying the disease of interest.
Nonresponse bias is the bias that occurs when the people who respond to a survey differ significantly from the people who do not respond to the survey.
A distortion that modifies an association between an exposure and an outcome because a factor is independently associated with the exposure and the outcome. Randomization is the best way to reduce the risk of confounding.
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This question is part of the following fields:
- Statistical Methods
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Question 12
Correct
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It was hypothesized that people that had lower socio economic status were more prone to developing gastric cancer. After 30 years of studying people with lower socio economic status, it was found that they did have a greater tendency to develop cancer. As a result of that the authors got to the conclusion that a strong association existed between the two. Later on another study conducted found that people from lower socio economic back grounds also had a tendency to be smokers.
Which form of potential bias can be associated with this particular study?Your Answer: Confounding bias
Explanation:Selection bias is when randomisation is not achieved and is often a result of in efficient recruiting method.
Recall bias is specifically appropriate to the case control studies that is when ever the memories retrieved by the participants differ in accuracy.
Measurement bias can be characterized by gathering of information in a manner that is distorted.
When the participants of a research study are recruited from the hospitals rather than the general population, its called Berkson Bias.
Confounding bias is the major player here because in this case the effects of smoking can be masked behind and can be read as outcomes of lower socio economic status. This extraneous factor (Smoking), distorts the founding.
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This question is part of the following fields:
- Statistical Methods
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Question 13
Incorrect
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Which of the following is true about number needed to harm?
Your Answer: The number of patients that must receive a particular treatment for one patient in that group to receive an adverse outcome.
Correct Answer: The number of patients that must receive a particular treatment for one additional patient to experience an adverse outcome.
Explanation:Number needed to harm are a measure of the impact of a treatment or intervention that is often used to communicate results to patients, clinicians, the public and policymakers. It states how many patients need to be treated for one additional patient to experience an adverse outcome (e.g. a death). It is calculated as the inverse of the absolute risk reduction. It can equally well be applied to harmful outcomes as well as beneficial ones, where it becomes numbers needed to treat (NNT) instead.
In this way, they are both calculated the same but NNT usually refers to a therapeutic treatment whereas NNH refers to a risk-factor for disease.
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This question is part of the following fields:
- Statistical Methods
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Question 14
Incorrect
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The required sample size in a trial of a new therapeutic agent varies with?
Your Answer: Experience of the investigator
Correct Answer: Level of statistical significance required
Explanation:The level of statistical significance required influences the sample size used. This is because sample size is used in the calculation of SD/SE.
Sample size does not affect
The level of acceptance
The alternative hypothesis with a general level set at p<0.05
The test to be used.Experience of the investigator and the type of patient recruited should have no bearing on the required sample size.
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This question is part of the following fields:
- Statistical Methods
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Question 15
Incorrect
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What is the percentage of values that lie within 3 standard deviations of the mean?
Your Answer: 97.20%
Correct Answer: 99.70%
Explanation:99.7% of the values within 3 standard deviations of the mean.
For 99.7% confidence interval, you can find the range as follows:
1. Multiply the standard error by 3.
2. Subtract the answer from mean value to get the lower limit.
3. Add the answer obtained in step 1 from the mean value to get the upper limit.
For a confidence interval of 68%, multiply the standard error with 1 and repeat the process. For a 95% confidence interval, Standard Error is multiplied by 1.96 to get the interval.
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This question is part of the following fields:
- Statistical Methods
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Question 16
Incorrect
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Drug X, a new intravenous induction drug, is being administered as a bolus at regular time intervals, and the following data were observed:
Time following injection (hours) vs Plasma concentration of drug X (mcg/mL)
2 / 400
6 / 100
10 / 25
14 / 6.25
Which of the following values estimate the plasma half-life (T½) of drug X?
Your Answer: 4 hours
Correct Answer: 2 hours
Explanation:Half life (T½) is the time required to change the amount of drug in the body by one-half (or 50%) during elimination. The time course of a drug in the body will depend on both the volume of distribution and the clearance.
Extrapolating the values from the plasma concentration vs time:
Plasma concentration at 0 hours = 800 mcg/mL
Plasma concentration at 2 hours = 400 mcg/mL
Plasma concentration at 4 hours = 200 mcg/mL
Plasma concentration at 6 hours = 100 mcg/mL
Plasma concentration at 8 hours = 50 mcg/mL
Plasma concentration at 10 hours = 25 mcg/mL
Plasma concentration at 12 hours = 12.5 mcg/mL
Plasma concentration at 14 hours = 6.25 mcg/mL -
This question is part of the following fields:
- Statistical Methods
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Question 17
Correct
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A new drug treatment has been developed for Crohn's disease. The pharmaceutical company behind this, is planning to conduct a trial and is looking for hiring around 200 individuals that are suffering from Crohn's disease. The aim would be to determine if there is any decline in the disease activity in response to the drug and compare it with a placebo.
What phase is the trial in?Your Answer: Phase 2
Explanation:The study is being conducted on a smaller level with only 200 participants and is determining the effectiveness of the drug in comparison to a placebo. These characteristics are in accordance with the second phase of trial.
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This question is part of the following fields:
- Statistical Methods
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Question 18
Correct
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The following results were obtained In a new drug trial:
Improved Not improved
Placebo group 36 26
Treatment group 44 16
Regarding the statistical analysis or interpretation of the trial, One of these is trueYour Answer: The data could be evaluated using the chi square test
Explanation:This data is in a 2 × 2 contingency table so a chi square test can be used. There is a special chi squared formula that gives a value that can be looked up in a table giving the p value.
Since we are comparing proportions not means, the Student’s t test CANNOT be used.
There is no linear regression to plot so Pearson’s co-efficient cannot be calculated.
Nothing is so obvious that no statistical analysis is needed.
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This question is part of the following fields:
- Statistical Methods
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Question 19
Incorrect
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The incidence and prevalence of a diabetes in a locality are being measured by a health care professional. This is what he found:
Year People with Diabetes New Cases
2017 150,000 2000
2018 150,000 4000
What can be stated regarding the incidence and prevalence of the disease in that area?Your Answer: Incidence increasing, prevalence decreasing
Correct Answer: Incidence increasing, prevalence equal
Explanation:Incidence tells us about the number of new cases that have been reported while prevalence gives us the idea of existing cases.
In this particular instance, the parameter of the study i.e. the total number of cases has not changed thus the prevalence of the disease remains same. Although, more cases have been reported in the second instance as a result of which incidence has increased.
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This question is part of the following fields:
- Statistical Methods
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Question 20
Correct
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During 2015 it was reported in the New England Journal of Medicine that the usage of empagliflozin(a sodium-glucose-co-transporter 2 inhibitor) caused a decrease in the cardiovascular deaths, non fatal heart attacks and strokes in patients suffering from type 2 diabetes. The results were published per 1000 patient years. With the above mentioned drug, the event rate turned out to be 37.3/1000 patient years whereas the placebo had an event rate of 43.9/1000 patient years.
How many further patients need to be treated with empagliflozin to avoid any further incidence of cardiovascular death or non fatal myocardial infraction and non fatal stroke?Your Answer: 150
Explanation:Number needed to treat can be defined as the number of patients who need to be treated to prevent one additional bad outcome.
It can be found as:
NNT=1/Absolute Risk Reduction (rounded to the next integer since number of patients can be integer only).
where ARR= (Risk factor associated with the new drug group) — (Risk factor associated with the currently available drug)
So,
ARR= (43.9-37.3)
ARR= 6.6
NNT= 1000/6.6
NNT=151.5
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This question is part of the following fields:
- Statistical Methods
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